KCET 2021 Physics Solved Paper

Let R and r be the radii of bigger and each smaller drop, respectively.
Volume of bigger drop =8× Volume of smaller drop
⇒

4

3

πR2=8×

4

3

πr3
or R=2r ...(i)
As, capacitance of a smaller spherical drop is
C=4πε0r
⇒ C ∝ r
So,

Cbigger

Csmaller

=

rbigger

rsmaller

=

R

r

=

2r

r

=2 [using Eq. (i)]
So, capacitance of bigger drop is two times as compared to each smaller drop.