KCET 2021 Physics Solved Paper

Given, XL=XC=4Ω
∴ Voltage across XC and XL is same in magnitude but opposite in direction. So, net voltage is
Vnet=VC−VL=0
Since, the voltmeter is connected across the series connection of capacitor and inductor. So, the reading of voltmeter is equal to Vnet i.e., zero. Current in the circuit,
I=

V

Z

=

V

√R2+(XL−XC)2

=

90

√(45)5+(4−4)2

=

90

45

=2A