The equation of straight line which passes through the point (a \cos ^{3} \\theta, a \sin ^{3} \\theta) and perpendicular to x \sec \\theta+y {\cosec} \\theta=a is

Correct Answer is : xcosθ−ysinθ=acos2θ

\frac{x}{a}+\frac{y}{a}=a \cos \\theta

x \cos \\theta-y \sin \\theta=a \cos 2 \\theta

x \cos \\theta+y \sin \\theta=a \cos 2 \\theta

x \cos \\theta-y \sin \\theta=a \cos 2 \\theta

KCET 2021 Math Solved Paper

Question : 19 of 60

Marks: +1, -0

The equation of straight line which passes through the point (acos3θ,asin3θ) and perpendicular to x‌sec‌θ+y‌cosec‌θ=a is

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