KCET 2020 Math Solved Paper

𝑦-intercept of 𝑥 + 𝑦 = 5 is (0, 5)
𝑦-intercept of 𝑥 + 3𝑦 = 9 is (0, 3)
The intersection point of 𝑥 + 𝑦 = 5 and 𝑥 + 3𝑦 = 9 is (3, 2)
Therefore, the corner points are (0, 5), (0, 3), (3, 2)
At (0, 5), 𝑍 = 35
At (0, 3), 𝑍 = 21
At (3, 2), 𝑍 = 47
So, 𝑍max = 47 at (3, 2)