KCET 2020 Chemistry Solved Paper

In NO2+, the steric number of N is two (two sigma bonds). Thus, it is sp hybridized. Hence, the percentage s-character is =

1

2

×100=50%
In O3−, the steric number of N is three (three sigma bonds). Thus, it is sp2 hybridized. Hence the percentage s-character is =

1

3

×100=33.33%
In NH4+, steric number of N is four (four sigma bonds). Thus, it is sp3 hybridized. Hence, the percentage s-character is =

1

4

×100=25%