An electromagnetic wave is travelling in x-direction with electric field vector given by, E_y^{\to}= E_0 \sin(kx- \omegat)j^{\^} . The correct expression for magnetic field vector is

Correct Answer is : →Bz=E0Csin(kx−ωt)^k

B_y^{\to}= E_0/C \sin(kx- \omegat)j^{\^}

B_y^{\to}= E_0 C \sin(kx- \omegat)j^{\^}

B_z^{\to}= E_0/C \sin(kx- \omegat)k^{\^}

B_z^{\to}= E_0 C \sin(kx- \omegat)k^{\^}

KCET 2019 Physics Solved Paper

Question : 37 of 60

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An electromagnetic wave is travelling in x-direction with electric field vector given by,

→

=E0‌sin(kx−ωt)‌

. The correct expression for magnetic field vector is

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