KCET 2019 Physics Solved Paper

(A)
Given line have positive intercept but negative slope.
So its equation can be written as,
v = -mx + v0 …(1)
where m = tanθ =

v0

x0

By differentiating with respect to time we get,

dv

dt

=−m

dx

dt

= -mv
Now substituting the value of ‘v’ from equation (1) we get

dv

dx

= -m[ -mx + v0 ] = m2x−mv0
a = m2x−mv0
i.e., the graph between a and x should have positive slope but negative intercept on acceleration axis.
Hence option (A) is correct.