A random variable ‘X’ has the following probability distribution X 1 2 3 4 5 6 7 P(X) k - 1 3k k 3k 3k^2 k^2 k^2 + k Then the value of k is

KCET 2019 Math Solved Paper

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A random variable ‘X’ has the following probability distribution

X	1	2	3	4	5	6	7
P(X)	k - 1	3k	k	3k	3k2	k2	k2 + k

Then the value of k is

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