KCET 2018 Physics Solved Paper

Magnetic flux,ϕ = BA → (1)
where B is magnetic field; A is area.
Also, B = µH → (2)
where μ is permeability; H is magnetic field intensity
Substituting Eq. (2) in Eq. (1), we get
ϕ = (µH)A
or

ϕ

µ

=HA
Now, Area A has dimensions L2
And magnetic field intensity H=

Number of turns × Current

Metre

⇒ H has dimensions L−1A.
Therefore,

ϕ

µ

=L−1A×L2=LA
Hence, the dimensions of ratio of magnetic flux and permeability μ are [M0L1T0A1]