KCET 2018 Math Solved Paper

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Question : 58 of 60

Marks: +1, -0

∫

1

√3−6x−9x2

dx is equal to

sin−1(
3x+1
2
)+C
sin−1(
3x+1
6
)+C
1
3
sin−1(
3x+1
2
)+C
sin−1(
2x+1
3
)+C

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