KCET 2017 Physics Solved Paper

By Malus Law, we have
I=I0‌cos‌θ
Given, intensity of light from second polariser is half of that from the first polariser, so
⇒‌

I0

2

=I0cos2θ
⇒cos2θ=‌

1

2

⇒cos‌θ=

1

√2

⇒θ=cos−1(

1

√2

)
⇒θ=45°
Therefore, angle between the pass axes of polarisers is 45°.