KCET 2017 Physics Solved Paper

Given, height of object = 10 cm; radius of curvature = 15 cm; distance of object = 10 cm.
Since radius of curvature is 15 cm, so focal length =

15

2

=7.5cm
⇒f<uThus, the object is placed between centre of curvature and focus of the concave mirror.
Therefore, the image formed is magnified and inverted.