KCET 2017 Physics Solved Paper

The given figure is as follows:Equivalent resistance of R1 and R3 is R=‌

3×6

3+6

=2Ω
Equivalent resistance of R and R2 is R′=2+2=4Ω
Equivalent resistance of R' and R4 is R′′=‌

4×4

4+4

=2Ω
Thus, the equivalent resistance of entire circuit is (2+1)=3Ω
Now, current through cell =‌

4.5

3

=1.5
and thus, voltage across 3 Ω resistance =1.5V
Therefore, power dissipated =‌

V2

R

=‌

1.5×1.5

3

=0.75W