KCET 2017 Physics Solved Paper

Given, two charges +2 nC and −8 nC are placed distance d apart. Therefore,
When the charges are joined together, then
Now, ⇒

16

d2

=

9

d12

⇒d12=

9

16

d2
⇒d1=

3

4

d
Therefore, in order to have same repulsive force as before the new distance between them should be

3

4

d