KCET 2017 Math Solved Paper

Given vertices of a triangle is, (K, 0 ), (4, 0), (0, 2) and area of triangle is 4 sq. units.
We know that, area of triangle with vertices (x1,y1),(x2,y2)(x3,y3) is given by
A=|

x1	x2	x3
y1	y2	y3
z1	z2	z3

|
So, ⇒‌

1

2

|−2K+8|=4
⇒8−2K=±8
For +8, we have 8−2K=8⇒K=0
For –8, we have 8−2K=−8⇒K=8