KCET 2016 Physics Solved Paper

Given, horizontal component of Earth’s magnetic field = 3.0 G; angle of dip = 30°
Now, horizontal component = B cos (angle of dip)
⇒3.0G=B‌cos‌30°
⇒B=‌

3.0

cos‌30∘

=‌

3.0×2

√3

⇒B=2√3=3.464∼3.5G
Therefore, magnetic field of Earth at that location = 3.5 G