KCET 2016 Physics Solved Paper

Given, angle of projection of A = 30°; angle of projection of B = 45°; angle of projection of C = 60°. Range of A = RA; rangeof B=RB; range of C=RC
Now, Horizontal range
⇒R=‌

v02‌sin‌2‌θ

g

⇒R∝sin‌2‌θ
∴RA∝sin(2×30∘)=sin(60∘)
⇒RA=

√3

2

RB∝sin(2×45∘)=sin(90∘)
⇒RB=1
RC∝sin(2×60∘)=sin(120∘)
⇒RC=

√3

2

Thus, RA=RC<RB