If there are only one type of charge in the universe, then (E^{\to} Electric field, \overrightarrow{ds} →Area vector)

Correct Answer is : ∮→E•ds=0 if charge is outside, =qε0 if charge is inside

∮E^{\to}• \overrightarrow{ds} \neq 0 on any surface

∮ E^{\to}• \overrightarrow{ds} could not be defined

∮ E^{\to}• ds=\infty if charge is inside

∮E^{\to} • ds = 0 if charge is outside, = q / \\epsilon_0 if charge is inside

KCET 2016 Physics Solved Paper

Question : 16 of 60

Marks: +1, -0

If there are only one type of charge in the universe, then
(

→

Electric field,

→

→Area vector)

Go to Question:

Prev Question

Next Question