KCET 2016 Physics Solved Paper

Given, maximum speed,vmax=0.5ms−1; maximum acceleration,amax=1.0ms−1; angular frequency, ω=?
Now, we know vmax=ωA → (1)
where A is amplitude of oscillation.
Also,amax=ω2A → (2)
Using Eqs. (1) and (2), we get
‌

vmax

amax

=‌

ωA

ω2A

⇒‌

vmax

amax

=‌

1

ω

⇒ω=‌

amax

vmax

=‌

1.0

0.5

⇒ω=2‌rad‌s−1
Therefore, angular frequency of oscillation is 2rads−1