The order and degree of the differential equation [1+(\frac{dy}{dx})^2+\sin(\frac{dy}{dx})]^{3/4} =\frac{d^2y}{dx^2}

Correct Answer is : order=2,degree=notdefined

\table \order=2\text{,}\degree=3

\table \order=2\text{,}\degree=4

\table \order=2\text{,}\degree=3/4

\table \order=2\text{,}\degree=\not \defined

KCET 2016 Math Solved Paper

Question : 35 of 60

Marks: +1, -0

The order and degree of the differential equation [1+(

)2+sin(

)]

d2y

dx2

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