KCET 2015 Physics Solved Paper

Given, P=2Ω;Q=2Ω;R=2Ω;S=3Ω
Balance equation gives

P

Q

=

R

S

Suppose the resistance S is shunted with resistance X, then balance equation becomes
‌

P

Q

=‌

P

(‌ SX S+X )

Substitute the values, we get
⇒3X=6+2X⇒X=6Ω
Therefore, S is to be shunted with 6 Ω resistance in order tobalance the bridge