KCET 2015 Math Solved Paper

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Question : 8 of 60

Marks: +1, -0

If |

2a	x1	y1
2b	x2	y2
2c	x3	y3

|=

abc

2

≠ 0, then the area of the triangle whose vertices are (

x1

a

,

y1

a

),(

x2

b

,

y2

b

),(

x3

c

,

y3

c

) is

1
4
abc
1
8
abc
1
4
1
8

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