KCET 2015 Chemistry Solved Paper

For the esterification reaction
r1=k[CH3COOH][CH3OH]
=k[1][2]
r1=2k → (1)
when solution is diluted with equal volume of water, concentration is reduced to half
r2=k[‌

1

2

][‌

2

2

]
r2=‌

k

2

→ (2)
Divide Eq. (1) by Eq. (2), we get
‌

r1

r2

=‌

2k

k 2

=4
r2=‌

r1

4

=0.25r1
Therefore, the rate of the reaction will reduce to 0.25 times of the initial rate.