KCET 2014 Physics Solved Paper

Initial velocity = 0 and acceleration is constant.
Distance travelled in first half of time =x1
Distance travelled in next half of time =x2
Therefore, acceleration =‌

x2−x1

t2

→ (1)
Now, x1=

1

2

at2 because initial velocity is zero. Substitute in Eq. (1), we get
a=‌

x2− 1 2 at2

t2

⇒at2=x2−‌

1

2

at2
⇒x2=at2+‌

1

2

at2
⇒x2=3×‌

1

2

at2
Thus x2=3x1