Equation of circle with center (-a, - b) and radius \sqrt{a^2- b^2} is

Correct Answer is : x2+y2+2ax+2by+2b2=0

x^2 + y^2 - 2ax - 2by - 2b^2 = 0

x^2 + y^2- 2ax + 2by + 2a^2 = 0

x^2 + y^2 + 2ax + 2by + 2b^2 = 0

x^2 + y^2 - 2ax - 2by + 2b^2 = 0

KCET 2014 Math Solved Paper

Question : 44 of 60

Marks: +1, -0

Equation of circle with center (-a, - b) and radius √a2−b2 is

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