Conductivity of a saturated solution of a sparingly soluble salt AB at 298 K is 1.85 \times 10^{-5} S m^{-1}. Solubility product of the salt AB at 298 K is Given ∧^\circ_\m(AB) = 140 \times10^{-4} S \m^2 mol^{-1}

Correct Answer is : 1.74×10−12

KCET 2014 Chemistry Solved Paper

Question : 32 of 60

Marks: +1, -0

Conductivity of a saturated solution of a sparingly soluble salt AB at 298 K is 1.85×10−5Sm−1. Solubility product of the salt AB at 298 K is

Given ∧°m(AB)=140×10−4S m2mol−1

1.32×10−12
1.74×10−12
5.7×10−12
7.5×10−12

Validate

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