The equilibrium constant of the reaction: A_(s)+2B^{+}_(aq)⇌A^{2+}_(aq)+2B_(s); E^\circ_{\text{cell}}=0.0295V is [(2.303RT)/F=0.059]

KCET 2012 Chemistry Solved Paper

Question : 5 of 60

Marks: +1, -0

The equilibrium constant of the reaction:
A(s)+2B(aq)+⇌A(aq)2++2B(s);E°cell=0.0295V is
[

(2.303RT)

=0.059]

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