If A=\left[\begin{array}{cc}1 & 2 \ 3 & 4]\end{array}, then A^{-1}=

Correct Answer is : −12[4−2−31]

\frac{-1}{2}\left[\begin{array}{cc}4 & -2 \ -3 & 1]\end{array}

\frac{1}{2}\left[\begin{array}{cc}4 & -2 \ -3 & 1]\end{array}

\left[\begin{array}{cc}-2 & 4 \ 1 & 3]\end{array}

\left[\begin{array}{cc}2 & 4 \ 1 & 3]\end{array}

KCET 2008 Math Solved Paper

Question : 36 of 60

Marks: +1, -0

If A=[

1	2
3	4

], then A−1=

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4	−2
−3	1

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−2	4
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