\frac{3 x^2+1}{x^2-6 x+8} is equal to

Correct Answer is : 3+492(x−4)−132(x−2)

\frac{49}{2(x-4)}-\frac{13}{2(x-2)}

3+\frac{49}{2(x-4)}-\frac{13}{2(x-2)}

\frac{49}{2(x-4)}+\frac{13}{2(x-2)}

\frac{-49}{2(x-4)}+\frac{13}{2(x-2)}

KCET 2007 Math Solved Paper

Question : 5 of 60

Marks: +1, -0

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3x2+1

x2−6x+8

is equal to

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