x=4(1+{\Cos} \theta) and y=3(1+{\Sin} \theta) are the parametric equations of

Correct Answer is : (x−4)216+(y−3)29=1

\frac{(x-4)^2}{16}+\frac{(y-3)^2}{9}=1

\frac{(x-4)^2}{16}-\frac{(y-3)^2}{9}=1

\frac{(x+4)^2}{16}+\frac{(y+3)^2}{9}=1

\frac{(x-3)^2}{9}+\frac{(y-4)^2}{16}=1

KCET 2006 Math Solved Paper

Question : 31 of 60

Marks: +1, -0

x=4(1+Cos‌θ) and y=3(1+Sin‌θ) are the parametric equations of

Go to Question:

Prev Question

Next Question