Inverse of the matrix \left[\begin{array}{c}{\Cos\end{array} 2 \theta , -{\Sin} 2 \theta ; {\Sin} 2 \theta , {\Cos} 2 \theta]} is .......

Correct Answer is : [Cos2θSin2θ−Sin2θCos2θ]

\left[\begin{array}{c}{\Cos\end{array} 2 \theta , -{\Sin} 2 \theta ; {\Sin} 2 \theta , {\Cos} 2 \theta]}

\left[\begin{array}{c}{\Cos\end{array} 2 \theta , {\Sin} 2 \theta ; {\Sin} 2 \theta , -{\Cos} 2 \theta]}.

\left[\begin{array}{c}{\Cos\end{array} 2 \theta , {\Sin} 2 \theta ; {\Sin} 2 \theta , {\Cos} 2 \theta]}

\left[\begin{array}{c}{\Cos\end{array} 2 \theta , {\Sin} 2 \theta ; -{\Sin} 2 \theta , {\Cos} 2 \theta]}

KCET 2004 Math Solved Paper

Question : 21 of 60

Marks: +1, -0

Inverse of the matrix [

Cos‌2‌θ	−Sin‌2‌θ
Sin‌2‌θ	Cos‌2‌θ

] is .......

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