The velocity constant of a reaction at 290^{\circ} {\K} was found to be 3.2 \times 10^{-3} {\S}^{-1}. When the temperature is raised to 310^{\circ} {\K}, it will be about :

Correct Answer is : 1.28×10−2

KCET 2004 Chemistry Solved Paper

Question : 46 of 60

Marks: +1, -0

The velocity constant of a reaction at 290∘K was found to be 3.2×10−3S−1. When the temperature is raised to 310∘K, it will be about :

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