JEE Mains Model Paper 9

Circle x2 + y2 − 4x − 8y − 5 = 0
Centre = (2, 4).
Radius = √4+16+5 = 5
If circle is intersecting line 3x − 4y = m
at two distinct points.
⇒ length of perpendicular from centre < radius
⇒

|6−16−m|

5

< 5
⇒ |10 + m| < 25
⇒ − 25 < m + 10 < 25
⇒ − 35 < m < 15