JEE Mains Model Paper 9

In positive beta decay a proton is transformed into a neutron and a positron is emitted
p+ → n0 + e+
no. of neutrons initially was A − Z
no. of neutrons after decay (A − Z) − 3 × 2 (due to alpha particles) + 2 × 1 (due to positive beta decay)
The no. of proton will reduce by 8. [as 3 × 2 (due to alpha particles) + 2 (due to positive beta decay)]
Hence atomic number reduces by 8.