JEE Mains Model Paper 8

© examsiri.com
Question : 62 of 90
 
Marks: +1, -0
For 2 different gases at different temperatures, the relation for rms velocity is
C1
C2
= √
T1
T2
×
M1
M2
. Then if rms velocity of 32 grams of O2 at 27°C and 3 atm pressure is 10 mt/s and kinetic energy is900 cal. At 27° and 6 atm pressure kinetic energy of 2 grams of H2 is x × 100 cal. Value of 'x' is
Go to Question: