If 2^\sqrt{\sin^2x-2sinx+5} 1/{4^{sin2y}} ≤ 1, then the ordered pair (x, y) is equal to (m, n ∈ I)

Correct Answer is : x = (4n + 1) π2 , y = (2m + 1) π2

x = (4n + 1) \pi/2 , y = (2m + 1) \pi/2

x = (2n + 1) \pi/2 , y = (2m + 1) \pi/2

JEE Mains Model Paper 8

Question : 28 of 90

Marks: +1, -0

If 2√sin2x−2sinx+5

4sin2y

≤ 1, then the ordered pair (x, y) is equal to (m, n ∈ I)

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