JEE Mains Model Paper 8

cos 6x + 6 cos 4x + 15 cos 2x + 10 = cos 6x + cos 4x + 5 (cos 4x + cos 2x) +10 (cos 2x + 1)= 2 cos x (cos 5x + 5 cos 3x + 10 cos x)
⇒

1

2

∫ secx dx =

1

2

ln (secx + tanx) + c
=

1

2

ln (

1+sinx

cosx

) + c
=

1

2

ln tan (

x

4

+

π

4

) + c