JEE Mains Model Paper 8

Normal at (0, −3) is 2x − y − 3 = 0
Solving with the given equation
x = 0, 1, −1; y = −3, −1, −5
i.e (0, −3), (1, −1) ,(−1, −5)
since x1 > x2 we have Q = (1,−1);
R = (−1, −5) equation of tangent at Q is 2x − y − 3 = 0