The vector equation of the plane through the point 2i^{\^}-j^{\^}-4k^{\^} and parallelto the plane r^{\to} . (4i^{\^}-12j^{\^}-3k^{\^}) - 7 = 0 is

Correct Answer is : →r . (4^i−12^j−3^k) = 32

r^{\to} . (4i^{\^}-12j^{\^}-3k^{\^}) = 0

r^{\to} . (4i^{\^}-12j^{\^}-3k^{\^}) = 32

r^{\to} . (4i^{\^}-12j^{\^}-3k^{\^}) = 12

JEE Mains Model Paper 5

Question : 85 of 90

Marks: +1, -0

The vector equation of the plane through the point 2

−

−4

and parallelto the plane

→

. (4

−12

−3

) - 7 = 0 is

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