An electron(mass m) with an initial velocity v = v_0i^{\^} is in an electric field E = E_0j^{\^}. If \lambda_0 = h/{mv_0} , its de-Broglie wavelength at time t is given by

Correct Answer is : λ0√1+e2E02t2m2v02

\lambda_0\sqrt{1+\frac{e^2E_0^2t^2}{m^2v_0^2}}

{\lambda_0}/\sqrt{1+\frac{e^2E_0^2t^2}{m^2v_0^2}}}

{\lambda_0}/{({1+\frac{e^2E_0^2t^2}{m^2v_0^2}})}

JEE Mains Model Paper 4

Question : 54 of 90

Marks: +1, -0

An electron(mass m) with an initial velocity v = v0

is in an electric field E = E0

. If λ0 =

mv0

, its de-Broglie wavelength at time t is given by

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