JEE Mains Model Paper 4

Given x and y are the sides of two squares such that y - x - x2
∴ Area of the first square A1 = x2
And area of the second square , A2 = y2 = (x−x2)2
∴

dA1

dt

=

d

dt

(x2) = 2x .

dx

dt

And ∴

dA2

dt

=

d

dt

(x−x2)2 = 2x (x - x2) (1 - 2x)

dx

dt

∴

dA1

dA1

=

(1−2x)2x(1−x)

2x

= 2x2−3x+1