JEE Mains Model Paper 4

Let the coordinates of D be (x,y,z).

AB = √(5−2)2+(6−2)2+(9+3)2 = 13 ;
AC = √(2−2)2+(7−2)2+(9+3)2 = 13
Thus, ABC is isosceles triangle with AB=ACSo, angle bisector AD bisects BC or we can say that D is mid point of BC.
∴ D = (

7

2

,

13

2

,9)