JEE Mains Model Paper 23

(4) The capacitance of first capacitor C1 = 3 µF
The capacitance of second capacitor C2 = 2 µF
Voltage across first capacitor V1 = 300 V
Voltage across second capacitor V2 = 200 V
In parallel combination, charge across first capacitor q1 = C1V1 = 3 × 300 = 900 µC
Charge across second capacitor q2 = C2V2 = 2 × 200 = 400 µC
Therefore, total charge in circuit q = q1+q2 = 900 + 400 = 1300 µC
and common voltage is 100 V, so the charge flow through the connecting wire is 600 µC