The equilibrium constant K for the reaction 1/2F_2 (g) ⇌ F (g) at 842 °C is 7.9 × 10^{-3} . What is K_p at the same temperature

Correct Answer is : 7.56 × 10−3

JEE Mains Model Paper 22

Question : 42 of 90

Marks: +1, -0

The equilibrium constant K for the reaction

F2 (g) ⇌ F (g) at 842 °C is 7.9 × 10−3 . What is Kp at the same temperature

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