A coil of some internal resistance V behaves like an inductance. When it is connected in series with a resistance RI, the time constant is found to be \tau_1 . When it is connected in series with a resistance R2. the time constant is found to be \tau_2 . The inductance of the coil is.

Correct Answer is : τ1τ2(R1−R2)(τ2−τ1)

\frac{\tau_1\tau_2(R_1-R_2)}{(\tau_2-\tau_1)}

\frac{(\tau_2-\tau_1)}{\tau_1\tau_2(R_1-R_2)}

\frac{(R_1-R_2)}{(\tau_2-\tau_1)}

\frac{(\tau_2-\tau_1)}{(R_1-R_2)}

JEE Mains Model Paper 22

Question : 30 of 90

Marks: +1, -0

A coil of some internal resistance V behaves like an inductance. When it is connected in series with a resistance RI, the time constant is found to be τ1 . When it is connected in series with a resistance R2. the time constant is found to be τ2 . The inductance of the coil is.

τ1τ2(R1−R2)
(τ2−τ1)
(τ2−τ1)
τ1τ2(R1−R2)
(R1−R2)
(τ2−τ1)
(τ2−τ1)
(R1−R2)

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