The solution of x^3 \frac{dy}{dx} + 4x^2 tan y = e^x sec y satisfying y(1) = 0 is

Correct Answer is : sin y = (x - 1) ex x−4

JEE Mains Model Paper 21

Question : 89 of 90

Marks: +1, -0

The solution of x3

+ 4x2 tan y = ex sec y satisfying y(1) = 0 is

Go to Question:

Prev Question

Next Question