Let F^{\to} be force acting on a particle having position vector r^{\to} . Let \tau^{\to} G be the torque due to this forceabout the origin, then:

Correct Answer is : →r.→τ = 0 and →F.→τ = 0

r^{\to} . \tau^{\to} = 0 and F^{\to} . \tau^{\to} = 0

r^{\to} . \tau^{\to} = 0 but F^{\to} . \tau^{\to} ≠ 0

r^{\to} . \tau^{\to} ≠ 0 but F^{\to} . \tau^{\to} = 0

r^{\to} . \tau^{\to} ≠ 0 and F^{\to} . \tau^{\to} ≠ 0

JEE Mains Model Paper 20

Question : 40 of 90

Marks: +1, -0

Let

→

be force acting on a particle having position vector

→

. Let

→

G be the torque due to this forceabout the origin, then:

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