JEE Mains Model Paper 2

We have a+c = 2b ⇒ a+ b+c =3/2 ⇒ b= 1/2
Thus , a + c = 1 and a2c2 = b4 = 1/16
⇒ a2(1−a)2 = 1/16 ⇒ a (1 - a) = ±1/4
⇒ 4a2 - 4a ±1 = 0 ⇒ (2a−1)2 = 0 or (2a−1)2 = 2
⇒ a =

1

2

or a =

1

2

±

1

√2

As a < b < c and b = 1/2 we get a =

1

2

−

1

√2