JEE Mains Model Paper 2

Taking x common from C2, x + 1 from C3 and x - 1 from R3 , we get
Δ (x) = x (x + 1) (x - 1) |

1	1	1
2x	x−1	x
3x	x−2	x

|
Applying C1→C1−C3 , C2→C3 we get
Δ (x) = x (x + 1) (x - 1) |

0	0	1
x	−1	x
2x	−2	x

|
= 0 [ ∵ C1 and C2 are proportional]
Thus Δ (100) = 0