JEE Mains Model Paper 2

© examsiri.com
Question : 52 of 90
 
Marks: +1, -0
Photons of energies 4.25eV and 4.7eV are incident on two metal surfaces A and Brespectively. The maximum KE of emitted electrons are respectively TA eV and TB=(TA1.5) eV. The ratio de-Broglie wavelengths of photo electrons from them is λa:λB = 1 : 2 ; then work function of A and B
Go to Question: